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Q: What is the largest possible four-digit number that can be formed that is divisible by 3 and 6?

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It is: 996

1,005

How about: 108

It is: 1005

108

Whole numbers are divisible by 4 if the number formed by the last two individual digits is evenly divisible by 4. For example, the number formed by the last two digits of the number 2628 is 28, which is evenly divisible by 4 so the number 2628 is evenly divisible by 4.

If the number formed by the last three digits is divisible by 8. Alternatively, if the number is divisible by 2, the quotient is divisible by 2 and that quotient is divisible by 2.

The digital root (sum of digit) must be divisible by 9, and the number formed by the last 4 digits must be divisible by 16. The second requirement ensures that the number is divisible by 16.

If the last three digits of a number are divisible by 8, the whole number is divisible by 8.

A number is divisible by 4 if the number formed by its last two digits is divisible by 4.Equivalently, halve the number formed by the last two digits. If the quotient is even, then the original number is divisible by 4.

I don't know the answer so please would you answer it

The largest integer that can be formed by using the digits only once each and simply arranging them in some order is 8740. Otherwise, using exponents, much larger numbers are possible.

numbers that are divisible by 4 is either: 4n or numbers in which the number formed by last two digits are divisible by 4

The digital root of 432 is 9 so the number is divisible by 3. The number formed by the last two digits, 32, is divisible by 4 (4*8) so 432 is divisible by 4.

Monocytes are the largest.

Numbers are divisible by 8 if the number formed by the last three individual digits is evenly divisible by 8. For example, the last three digits of the number 3624 is 624, which is evenly divisible by 8 so 3624 is evenly divisible by 8.

if the number formed by the last two digits is divisible by 4, then the whole number will be divisible by 4 for example, 932 is divisible by 4 because 32 is divisible by 4 19935 is not divisible by 4 because 35 is not divisible by 4 (note: if the last two digits are 00, the number is divisible by 4)

The number formed by the last three digits have to be divisible by 8.

The number formed by the last three digits must be divisible by 8.

There are 2000 such numbers.

If you don't want any odd digit, and don't want to repeat a digit, start with the largest possible digit, in this case 8, and keep adding the largest digit every time, until you run out of possibilities: 86420.

9650 is the largest formed by re-ordering the digits.

The 2-digit number formed by the last two digits is divisible by 4.

192 ways

the largest five digit number that can be formed using the digits 7 and 9 is 97,000